calculation of intersection point of two straight lines

Y =  X + 
Y =  X + 
intersection point of two straight lines:

two straight lines: 2x-3y-3=0 and x+y+2=0, just solve the x and y values ​​simultaneously.

x+y+2=0 =>y=-x-2 substituting 2x-3y-3=0 we get =>2x+3x+6-3=0 =>x=-3/5 =>y=3/5 -2=-7/5

so the intersection point of the two straight lines is (-3/5, -7/5)