calculation of intersection point of two straight lines
two straight lines: 2x-3y-3=0 and x+y+2=0, just solve the x and y values ​​simultaneously.
x+y+2=0 =>y=-x-2 substituting 2x-3y-3=0 we get =>2x+3x+6-3=0 =>x=-3/5 =>y=3/5 -2=-7/5
so the intersection point of the two straight lines is (-3/5, -7/5)