1． the total power = the power of each series capacitor, that is, qt = q1 = q2 = q3....
2. total voltage = sum of voltages of each series capacitor, that is, e=v1+v2+v3....
3． the reciprocal of the total capacitance = the sum of the reciprocal capacitances of each series connection, that is, 1/ct = 1/c1 + 1/c2 +………
4． total energy = sum of energy of each series capacitor, that is, wt = w1 + w2 + w3....

withstand voltage calculation formula:

total voltage: u
U1=C2*U/(C1+C2)
U2=C1*U/(C1+C2)
example: c1 is 10uf and c2 is 22uf. from the above formula, it can be seen that the voltage across c1 is 15.62v and the voltage across c2 is 34.74v.when capacitors are connected in series, the voltage is inversely proportional to the capacitance value.

however, in actual work, due to various reasons, one of the capacitors breaks down, then the total voltage will be added to the other capacitor, which is not very reliable. therefore, series connection of high-voltage capacitors should be treated with caution.

for circuits with higher voltages, the series connection of capacitors will not be ideal for "automatically" distributing the withstand voltage, and separate voltage dividing resistors of hundreds of kω or mω must be added separately.